获得一个元素的所有兄弟元素节点，是需要包含它自己的对吗。得把它本身拼接上吗

来源：3-13 封装节点关系函数

张小阳_

2022-06-25 16:50:47

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<html lang="en">

<head>
    <meta charset="UTF-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>获得一个元素的所有兄弟元素节点</title>
</head>

<body>
    <div id="ele">
        <p>1</p>
        <p>2</p>
        <p id="third">3</p>
        <p>4</p>
        <p>5</p>
        <p>6</p>
    </div>

    <script>
        function getAllElementsSibling(node) {
            // 前面节点集合
            var pervs = [];
            // 后面节点集合
            var nexts = [];
            // 前面元素节点遍历
            var ret = node;
            while (ret.previousSibling != null) {
                if (ret.previousSibling.nodeType == 1) {
                    pervs.unshift(ret.previousSibling);
                }
                ret = ret.previousSibling;
            }
            // 后面元素节点遍历
            ret = node;
            while (ret.nextSibling != null) {
                if (ret.nextSibling.nodeType == 1) {
                    nexts.push(ret.nextSibling);
                }
                ret = ret.nextSibling;
            }
            return pervs.concat(node, nexts);
        };

        console.log(getAllElementsSibling(third));
    </script>
</body>

</html>