为什么我这个登录页面。当打开那个页面就显示用户不存在，请重新输入呢？
来源：1-2 用户注册表单验证
hello_phpinfo
2018-10-20 20:48:02
<?php
include_once './lib/func.php';
if(!empty($_POST['username'])){
$username=trim($_POST['username']);
$password=trim($_POST['password']);
if(!$username){
echo '用户名不能为空';
}
if(!$password){
echo '密码不能为空';
}
}
//数据库操作
$con=mysqlInit('127.0.0.1','root','','imooc_mall');
if(!$con){
echo mysql_errno();
exit;
}
//判断用户是否存在
@$sql="SELECT * FROM im_user WHERE username='{$username}' LIMIT 1";
$obj=mysql_query($sql);
$result=mysql_fetch_assoc($obj);
if(is_array($result)&&!empty($result)){
if(createPassword($password)===$result['password']){
echo '登录成功';
exit;
}else{
echo '密码输入错误,请重新输入';
exit;
}
}else{
echo '用户不存在,请重新输入';
}
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>M-GALLARY|用户登录</title>
<link type="text/css" rel="stylesheet" href="./static/css/common.css">
<link type="text/css" rel="stylesheet" href="./static/css/add.css">
<link rel="stylesheet" type="text/css" href="./static/css/login.css">
</head>
<body>
<div class="header">
<div class="logo f1">
<img src="./static/image/logo.png">
</div>
<div class="auth fr">
<ul>
<li><a href="login.php">登录</a></li>
<li><a href="register.php">注册</a></li>
</ul>
</div>
</div>
<div class="content">
<div class="center">
<div class="center-login">
<div class="login-banner">
<a href="#"><img src="./static/image/login_banner.png" alt=""></a>
</div>
<div class="user-login">
<div class="user-box">
<div class="user-title">
<p>用户登录</p>
</div>
<form class="login-table" name="login" id="login-form" action="login.php" method="post">
<div class="login-left">
<label class="username">用户名</label>
<input type="text" class="yhmiput" name="username" placeholder="Username" id="username">
</div>
<div class="login-right">
<label class="passwd">密码</label>
<input type="password" class="yhmiput" name="password" placeholder="Password" id="password">
</div>
<div class="login-btn">
<button type="submit">登录</button>
</div>
</form>
</div>
</div>
</div>
</div>
</div>
<div class="footer">
<p><span>M-GALLARY</span> ©2017 POWERED BY IMOOC.INC</p>
</div>
</body>
<script src="./static/js/jquery-1.10.2.min.js"></script>
<script src="./static/js/layer/layer.js"></script>
<script>
$(function () {
$('#login-form').submit(function () {
var username = $('#username').val(),
password = $('#password').val();
if (username == '' || username.length <= 0) {
layer.tips('用户名不能为空', '#username', {time: 2000, tips: 2});
$('#username').focus();
return false;
}
if (password == '' || password.length <= 0) {
layer.tips('密码不能为空', '#password', {time: 2000, tips: 2});
$('#password').focus();
return false;
}
return true;
})
})
</script>
</html>
1回答
-
好帮手慕查理
2018-10-21
您好，应该是你if嵌套的问题，按照顺序执行当执行到 if(is_array($result)&&!empty($result))判断时，用户不存在所以输出了提示语句。应该是先判断是登录，当登录时才执行此if判断语句。祝学习愉快！
0
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