老师帮我检查一下。
来源:2-4 编程练习
宝慕林4199460
2022-11-15 22:54:51
public class Employee{
//根据需求完成Employee类的定义
private int id;
private String name;
private double salary;
public Employee(){
}
public Employee(int id,String name,double salary){
this.setId(id);
this.setName(name);
this.setSalary(salary);
}
public int getId(){
return this.id;
}
public void setId(int id){
this.id=id;
}
public String getName(){
return this.name;
}
public void setName(String name){
this.name=name;
}
public double getSalary(){
return this.salary;
}
public void setSalary(double salary){
this.salary=salary;
}
}
import java.util.List;
import java.util.ArrayList;
public class EmployeeTest {
public static void main(String[] args) {
//定义ArrayList对象
ArrayList<Employee> empList=new ArrayList<Employee>();
//创建三个Employee类的对象
Employee one=new Employee(1,"张三",5000);
Employee two=new Employee(2,"李四",5500d);
Employee thr=new Employee(3,"赵六",4000d);
//添加员工信息到ArrayList中
empList.add(one);
empList.add(two);
empList.add(thr);
//显示员工的姓名和薪资
System.out.println("员工姓名 员工薪水");
for(int i=0;i<empList.size();i++){
System.out.println(empList.get(i).getName()+" "
+ empList.get(i).getSalary() );
}
}
}问题描述:
为什么不能直接用.name 来获取属性,而是要用getName()
empList.get(i).name
1回答
好帮手慕小小
2022-11-16
同学你好,name属性的访问权限修饰符为private,无法在类外部访问私有的成员,故需使用getName()来获取。同学代码实现符合题目要求,继续加油!

祝学习愉快~
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