老师，请问为什么无法捕捉到错误

来源：5-3 编程练习

慕数据5191420

2022-04-18 18:03:43

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta name="referrer" content="no-referrer" />
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>Document</title>
    <style>
        img{
            width: 300px;
            float: left;
        }
    </style>
</head>
<body>
    <div id="box">
        <img src="" alt="">
        <img src="" alt="">
        <img src="" alt="">
    </div>

    <script>
        const box = document.getElementById('box');
        let imgDom_0 = document.getElementsByTagName('img')[0];
        let imgDom_1 = document.getElementsByTagName('img')[1];
        let imgDom_2 = document.getElementsByTagName('img')[2];

        const loadImgAsync = url =>{

            return new Promise((resolve,reject)=>{
                const img = new Image();
                img.src = url;

                img.onload = setTimeout(() => {
                    resolve(img)
                }, 1000);

                img.onerror = setTimeout(() => {
                    reject(`Could not load image at ${url}`);
                }, 1000);

            })
        }

        loadImgAsync(`http://climg.mukewang.com/5b16558d00011ed506000338.jpg`)
        .then(
            img =>{
                console.log(img.src);
                imgDom_0.src = img.src;
                return loadImgAsync(`http://climg.mukewang.com/5b165603000146ca06000338.jpg`);
            }
        )
        // .catch(err=>console.log(err))
        .then(
            img =>{
                console.log(img.src);
                imgDom_1.src = img.src;
                return loadImgAsync(`http://climg.mukewang.com/5b1656140001c89906000338.jpg `);
            }
        ).then(
            img =>{
                console.log(img.src);
                imgDom_2.src = img.src;
            }
        )


    </script>
</body>
</html>

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