# coding:utf-8

import os

def create_package(path):
    if os.path.exists(path):
        raise Exception('%s 这个文件已存在不能创建' % path)
    os.makedirs(path)
    init_path = os.path.join(path, '__inint__.py')
    f = open(init_path, 'w')
    f.write('# coding:utf-8\n')
    f.close()

if __name__ == '__main__':
    current_path = os.getcwd()
    path = os.path.join(current_path, 'text1')
create_package(path)

class Open(object):
    def __init__(self, path, mode='w', is_return=True):
        self.path = path
        self.mode = mode
        self.is_return = is_return

    def write(self, message):
        f = open(self.path, mode=self.mode)
if self.is_return:
            if not message.endswith('\n'):
                message = '%s\n' % message
        try:
            f.write(message)
except Exception as e:
            print(e)
finally:
            f.close()


if __name__ =='__main__':
    current_path = os.getcwd()
# path = os.path.join(current_path, 'text1')
    # create_package(path)
    open_path = os.path.join(current_path, 'b.txt')
    o = Open(open_path)
    o.write('你好 小慕')

判断message后面是否有  \n  可以用  

​

if not message.endswith('\n'):

message = '%s\n' % message

    ​    ​这样写对吗?  不用判断 else会出问题吗?  或者继续用异常捕获这个语法呢?

不知道如果存在 \n 我这样写会不会出问题!