用ajax在console输出出来了echarts说我json is not defind？

来源：2-4 实现动态图表

wacky1

2020-06-05 11:01:33

<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Insert title here</title>
<script type="text/javascript" src="js/echarts.min.js"></script>
<script type="text/javascript" src="js/jquery-3.3.1.min.js"></script>
</head>
<body>
<div id="main" style="width: 600px;height:400px;"></div>
<script type="text/javascript">
		$.ajax({
			url:"./rt",
			type:"get",
			dataType:"json",
			success:function(json){
				console.log(json.timeList);
				console.log(json.valueList);
			}
			
		})
		
		
        // 基于准备好的dom，初始化echarts实例
        var myChart = echarts.init(document.getElementById('main'));

        // 指定图表的配置项和数据
        var option = {
            title: {
                text: '用户访问量'
            },
            tooltip: {},
            legend: {
                data:['访问量']
            },
            xAxis: {
                data: json.timeList
            },
            yAxis: {},
            series: [{
                name: '销量',
                type: 'line',
                data: json.valueList
            }]
        };

        // 使用刚指定的配置项和数据显示图表。
        myChart.setOption(option);
    </script>
</body>
</html>

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