不知道哪里错了,请老师看看
来源:2-2 创建XMLHttpRequest对象
慕仰7036876
2020-05-29 17:52:05
<!DOCTYPE html> <html> <head> <meta charset="UTF-8"> <title>Insert title here</title> </head> <script> document.getElementById("bthLoad").onclick = function(){ //创建XMLHttpRequest对象 var xmlhttp; if(window.XMLHttpRequest){ xmlhttp = new XMLHttpRequest(); } else{ xmlhttp = new ActiveXObject("Microsoft.XMLHTTP"); } console.log(xmlhttp); } </script> <body> <input id = "btnLoad" type = "button" value = "加载"> <div id = "divContent"></div> </body> </html>
package com.imooc.ajax; import java.io.IOException; import javax.servlet.ServletException; import javax.servlet.annotation.WebServlet; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; /** * Servlet implementation class ContentServlet */ @WebServlet("/Content") public class ContentServlet extends HttpServlet { private static final long serialVersionUID = 1L; /** * @see HttpServlet#HttpServlet() */ public ContentServlet() { super(); // TODO Auto-generated constructor stub } /** * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response) */ protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.getWriter().println("<b>i'm server content</b>"); } }
1回答
同学你好,1. 代码是从上到下进行执行的,当js代码在上方时,找到相应的属性导致报错,则建议同学将js代码放置到body标签的下面。
2. getElementById()中与id属性名不一致,则建议同学修改为btnLoad。修改后代码如下所示:
如果我的回答解决了你的疑惑,请采纳。祝:学习愉快~
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