不知道哪里错了,请老师看看
来源:2-2 创建XMLHttpRequest对象
慕仰7036876
2020-05-29 17:52:05
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Insert title here</title>
</head>
<script>
document.getElementById("bthLoad").onclick = function(){
//创建XMLHttpRequest对象
var xmlhttp;
if(window.XMLHttpRequest){
xmlhttp = new XMLHttpRequest();
}
else{
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
console.log(xmlhttp);
}
</script>
<body>
<input id = "btnLoad" type = "button" value = "加载">
<div id = "divContent"></div>
</body>
</html>package com.imooc.ajax;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class ContentServlet
*/
@WebServlet("/Content")
public class ContentServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public ContentServlet() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.getWriter().println("<b>i'm server content</b>");
}
}1回答
同学你好,1. 代码是从上到下进行执行的,当js代码在上方时,找到相应的属性导致报错,则建议同学将js代码放置到body标签的下面。
2. getElementById()中与id属性名不一致,则建议同学修改为btnLoad。修改后代码如下所示:

如果我的回答解决了你的疑惑,请采纳。祝:学习愉快~
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