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来源:2-13 自由编程
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2020-05-18 09:03:31
Notice.java
package pres.jstl.test2;
public class Notice {
private String ID;
private String name;
public Notice() {
}
public Notice(String ID,String name) {
this.setID(ID);
this.setName(name);
}
public void setID(String ID) {
this.ID=ID;
}
public String getID() {
return this.ID;
}
public void setName(String name) {
this.name=name;
}
public String getName() {
return this.name;
}
@Override
public String toString() {
return this.getID()+"——"+this.getName()+"!";
}
}NoticeServlet.java
package pres.jstl.test2;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet("/notice")
public class NoticeServlet extends HttpServlet{
private static final long serialVersionUID = 1L;
List<Notice> list = new ArrayList<>();
@Override
protected void service(HttpServletRequest request,HttpServletResponse response) throws ServletException, IOException {
Notice notice1 = new Notice("001","欢迎来到慕课网");
Notice notice2 = new Notice("002","欢迎学习Java Web课程");
Notice notice3 = new Notice("003","一定要多写代码,多练习哟");
list.add(notice3);
list.add(notice2);
list.add(notice1);
request.setAttribute("list",list);
request.getRequestDispatcher("/test4.jsp").forward(request,response);
}
}test4.jsp
<%@ page language="java" contentType="text/html;charset=UTF-8"
pageEncoding="UTF-8"%>
<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
<!DOCTYPE HTML>
<html>
<head>
<meta charset="UTF-8">
<title>测试页4</title>
</head>
<body>
<h2>公告展示</h2>
<c:forEach items="${requestScope.list }" var="notice" varStatus="idx">
<h3>${notice }</h3>
</c:forEach>
</body>
</html>1回答
同学你好,定义全局list集合,在每次访问时,将数据中进行添加集合,导致添加多条数据,则建议同学设置局部变量,将list集合定义在service()方法中,当访问时,都重新生成集合。如下所示:

如果我的回答解决了你的疑惑,请采纳!祝学习愉快!
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