老师,帮忙看一下这什么情况,为什么提示404未找到?
来源:2-7 利用Ajax实现新闻列表
黎明灬
2020-03-06 18:51:31
package com.imooc.ajax; import java.io.IOException; import java.util.ArrayList; import java.util.List; import javax.servlet.ServletException; import javax.servlet.annotation.WebServlet; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.alibaba.fastjson.JSON; @WebServlet("/news_list") public class NewsListServlet extends HttpServlet { private static final long serialVersionUID = 1L; public NewsListServlet() { super(); } /** * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response) */ protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { List <News>list=new ArrayList<News>(); list.add(new News("TIOBE:2018年5月","2018-5-1","TIOBE","...")); list.add(new News("TIOBE:2018年6月","2018-6-1","TIOBE","...")); list.add(new News("TIOBE:2018年7月","2018-7-1","TIOBE","...")); list.add(new News("TIOBE:2018年8月","2018-8-1","TIOBE","...")); list.add(new News("TIOBE:2018年9月","2018-9-1","TIOBE","...")); String json=JSON.toJSONString(list); System.out.println(json); response.getWriter().println(json); response.setContentType("text/html;charset=utf-8"); } }
1回答
好帮手慕阿莹
2020-03-06
1、从同学贴的图片和代码看起来没有问题。
可以如下试一下
1、重新编译一下-public -clean
2、查看一下tomcat中是否有把这个项目添加进去呢?例如:
3、看一下web.xml的版本是否是2.5的呢?如果是,建议改成3.1试试
如果我的回答解决了你的问题,请采纳,祝学习愉快.
相似问题