老师你好,帮忙看一看有需要改进的没
来源:2-6 自由编程
ByteDancer07
2020-02-15 16:23:37
HTML
<!DOCTYPE html> <html> <head> <meta charset="utf-8"> <title>Insert title here</title> <script type="text/javascript" scr="checkNum.js"></script> </head> <body> <form action="/ServletPro/num"> <input type = "text" id="num" name="num" placeholder="请输入100以内的数字"> <input type="submit" value="求累加和" onclick="checkNum()" > </form> </body> </html>
计算累积和的Servlet页面
package com.kai.servlet.pracrtise;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class Number
*/
@WebServlet("/num")
public class Number extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public Number() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
int sum=0;
int num =Integer.parseInt(request.getParameter("num"));
for(int i=0;i<=num;i++) {
sum=sum+i;
}
request.setAttribute("sum", sum);
request.getRequestDispatcher("/sum").forward(request, response);
System.out.println(sum);
}
}展示累积和
package com.kai.servlet.pracrtise;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class Number
*/
@WebServlet("/num")
public class Number extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public Number() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
int sum=0;
int num =Integer.parseInt(request.getParameter("num"));
for(int i=0;i<=num;i++) {
sum=sum+i;
}
request.setAttribute("sum", sum);
request.getRequestDispatcher("/sum").forward(request, response);
System.out.println(sum);
}
}还要个问题就是,应该怎么校验输入的数字是在0-100?
2回答
同学你好!
代码完整的不错
可以只是用js来实现。表单提交是需要使用onsubmit,这样可以根据函数的返回值来决定是否提交表单。如果返回ture则提交否则不提交。参考代码:

如果我的回答解决了你的疑惑,请采纳,祝学习愉快~
好帮手慕小班
2020-02-15
同学你好,1、路径为/sum的对应Servlet,同学并没有贴出,建议同学将代码贴全。
2、同学是想说在html页面中直接判断数字是否是小于100,同学可以等后面的jquery与正则表达式的课程完成后,再来尝试这个内容哟。
如果我的回答解决了你的疑惑,请采纳。祝:学习愉快~
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