为什么这样写显示不出来？
来源：2-9 自由编程
慕先生8145006
2019-10-03 14:24:15
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<%@ taglib uri = "http://java.sun.com/jsp/jstl/core" prefix="c" %>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Insert title here</title>
</head>
<body>
<% String day = (String)request.getAttribute("day"); %>
<c:choose>
<c:when test="${day == 'MONDAY' }">
<h2>星期一</h2>
</c:when>
<c:when test="${day == 'TUESDAY' }">
<h2>星期二</h2>
</c:when>
<c:when test="${day == 'WEDNESDAY' }">
<h2>星期三</h2>
</c:when>
<c:when test="${day == 'THURSDAY' }">
<h2>星期四</h2>
</c:when>
<c:when test="${day == 'FRIDAY' }">
<h2>星期五</h2>
</c:when>
<c:when test="${day == 'SATURDAY' }">
<h2>星期六</h2>
</c:when>
<c:when test="${day == 'SUNDAY' }">
<h2>星期日</h2>
</c:when>
<c:otherwise>
<h2>内容不对呦!</h2>
</c:otherwise>
</c:choose>
</body>
</html>
package com.imooc.jstl;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class XingqiServlet
*/
@WebServlet("/xingqi")
public class XingqiServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public XingqiServlet() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
request.setAttribute("day", "SUNDAY");
request.getRequestDispatcher("/xingqi.jsp").forward(request, response);
}
}
1回答
-
同学你好！
同学的代码没有问题呢，同学没有显示的原因是因为访问的地址不正确哦，同学直接访问了jsp文件
同学应该访问Servler呢，比如：
如果我的回答解决了你的疑惑，请采纳，祝学习愉快~
0
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