空指针异常

来源:2-6 自由编程

德里克rose

2019-08-23 10:43:57

http://img.mukewang.com/climg/5d5f52ce0001efb015090884.jpg

package com.imooc.servlet;


import java.io.IOException;


import javax.servlet.ServletException;

import javax.servlet.annotation.WebServlet;

import javax.servlet.http.HttpServlet;

import javax.servlet.http.HttpServletRequest;

import javax.servlet.http.HttpServletResponse;


/**

 * Servlet implementation class SumServlet

 */

@WebServlet("/SumServlet")

public class SumServlet extends HttpServlet {

private static final long serialVersionUID = 1L;

       

    /**

     * @see HttpServlet#HttpServlet()

     */

    public SumServlet() {

        super();

        // TODO Auto-generated constructor stub

    }


/**

* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)

*/

@Override

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

String number=request.getParameter("number");

int n=Integer.parseInt(number);

int sum=0;

for(int i=1;i<=n;i++){

sum=sum+i;

}

String num=Integer.toString(sum);

request.setAttribute("sum", num);

request.getRequestDispatcher("/sum2").forward(request, response);

}


}


写回答

1回答

好帮手慕柯南

2019-08-23

同学你好!

同学在访问地址是忘记传参数了

http://img.mukewang.com/climg/5d5f89aa000100ba04970117.jpg

所以后台获取到的值转不了数字就报错了,同学在后面拼接上要传的参数,或者直接在通过页面来访问servlet

如果我的回答解决了你的疑惑,请采纳,祝学习愉快~


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