老师,点击第一个按钮获取不到json数据是怎么回事
来源:3-6 自由编程
z晓龙
2019-07-26 22:25:23
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Insert title here</title>
<style type="text/css">
.btn{
width: 33%;
}
.div1{
text-align: center;
}
</style>
<script type="text/javascript" src="js/jquery-3.4.1.js"></script>
<script type="text/javascript">
$("#fashion").click(function(){
$.ajax({
"url" : "/ajax/song",
"type" : "get",
"data" : {"t" : "fashion"},
"dataType" : "json",
"success" : function(json){
console.log(json);
}
})
})
</script>
</head>
<body>
<input id="fashion" class="btn" type="button" value="流行歌曲" />
<input id="classic" class="btn" type="button" value="经典歌曲" />
<input id="rock" class="btn" type="button" value="摇滚歌曲" />
<div id="container" class="div1"></div>
</body>
</html>
package com.imooc.practice;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import com.alibaba.fastjson.JSON;
/**
* Servlet implementation class SongServlet
*/
@WebServlet("/song")
public class SongServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public SongServlet() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String type = request.getParameter("t");
List list = new ArrayList();
if(type != null && type.equals("fashion")) {
list.add(new Song("稻香"));
list.add(new Song("晴天"));
list.add(new Song("告白气球"));
}else if(type != null && type.equals("classic")) {
list.add(new Song("千千阙歌"));
list.add(new Song("傻女"));
list.add(new Song("七友"));
}else if(type!= null || type.equals("rock")) {
list.add(new Song("一块红布"));
list.add(new Song("假行僧"));
list.add(new Song("新长征路上的摇滚"));
}else {
System.out.println("无");
}
String json = JSON.toJSONString(list);
System.out.println(json);
response.setContentType("text/html;charset=UTF-8");
response.getWriter().println(json);
}
}1回答
好帮手慕阿莹
2019-07-27
同学你好,同学把js代码放到页面的最后试试,否则,当加载到js时,获取#fashion的时候,还没加载到html中的该元素。,放到页面的底部后,最后加载。就可以加载到了,再点击就有数据了。

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