点击按钮以后没有反应
来源:2-3 发送请求及处理响应
China_Wang
2019-05-08 12:06:22
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Title</title>
</head>
<body>
<input id="btnLoad" type="button" value="加载">
<div id="divContent"></div>
<!--<script type="text/javascript" src="js/jquery-3.4.1.js"></script>-->
<script>
document.getElementById("btnLoad").onclick = function () {
//1.创建XmlHttpRequest对象
var xmlhttp;
if(window.XMLHttpRequest){
xmlhttp = new XMLHttpRequest();
}
else {
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
console.log(xmlhttp);
//2.发送Ajax请求
xmlhttp.open("GET","http://localhost:8080/ajax/content",true);
xmlhttp.send();
//3.处理服务器响应
xmlhttp.readystatechange = function () {
console.log("xmlhttp.readyState:"+xmlhttp.readyState);
console.log("xmlhttp.status:"+xmlhttp.status);
//判断服务器处理状态
if(xmlhttp.readyState === 4 && xmlhttp.status === 200){
var text = xmlhttp.responseText;
console.log(text);
}
}
}
</script>
</body>
</html>package com.imooc.ajax;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;
@WebServlet(name = "ContentServlet",urlPatterns = "/content")
public class ContentServlet extends HttpServlet {
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.getWriter().println("<b>I'm Server Content</b>");
}
}1回答
同学你好!同学的单词拼写错误呢,应该是onreadystatechange

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