点击按钮以后没有反应
来源:2-3 发送请求及处理响应
China_Wang
2019-05-08 12:06:22
<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>Title</title> </head> <body> <input id="btnLoad" type="button" value="加载"> <div id="divContent"></div> <!--<script type="text/javascript" src="js/jquery-3.4.1.js"></script>--> <script> document.getElementById("btnLoad").onclick = function () { //1.创建XmlHttpRequest对象 var xmlhttp; if(window.XMLHttpRequest){ xmlhttp = new XMLHttpRequest(); } else { xmlhttp = new ActiveXObject("Microsoft.XMLHTTP"); } console.log(xmlhttp); //2.发送Ajax请求 xmlhttp.open("GET","http://localhost:8080/ajax/content",true); xmlhttp.send(); //3.处理服务器响应 xmlhttp.readystatechange = function () { console.log("xmlhttp.readyState:"+xmlhttp.readyState); console.log("xmlhttp.status:"+xmlhttp.status); //判断服务器处理状态 if(xmlhttp.readyState === 4 && xmlhttp.status === 200){ var text = xmlhttp.responseText; console.log(text); } } } </script> </body> </html>
package com.imooc.ajax; import javax.servlet.ServletException; import javax.servlet.annotation.WebServlet; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import java.io.IOException; @WebServlet(name = "ContentServlet",urlPatterns = "/content") public class ContentServlet extends HttpServlet { protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.getWriter().println("<b>I'm Server Content</b>"); } }
1回答
同学你好!同学的单词拼写错误呢,应该是onreadystatechange
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